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Chassis Design
Updated: Jan 28, 2022
"Adding power makes you faster on the straights, subtracting weight makes you faster everywhere."
- Anthony Colin Bruce Chapman
Basic requirements:
The body should be light.
It should have minimum number of components.
It should provide sufficient space for passengers and luggage.
It should withstand vibrations while in motion.
It should offer minimum resistance to air.
It should be cheap and easy in manufacturing.
It should have uniformly distributed load.
It should have long fatigue life.
It should provide good vision and ventilation.
Load cases:
The vehicle designer should know the load conditions in order to ensure the structure doesn’t fail due to some instantaneous load.
Some Basic Load Cases-
Bending-
In static condition (vehicle at rest or moving with constant velocity) :
1. Loading (due to the weight of components distributed along the vehicle frame) in vertical plane (let, x-z plane) cause bending about the y-axis.
2. Unsprung mass do not impose loads in static condition.
3. Determination and Result:
Static condition vehicle structure can be treated as 2D beam because vehicle is approximate symmetry at x-y plane.
Can be solved using static equilibrium balance.
Results in set of algebraic equation.
In dynamic condition (vehicle moving at variable velocity or vehicle moving at bumpy road even at constant velocity) :
1. Inertia of the structure contributes in total loading
2. Always higher than static loading
(For road vehicles: 3 times than static loads; For off-road vehicles: 4 times than static load)
3. Determination and result:
Can be solved using dynamic equilibrium balance.
Generally results in differential equation.
Torsion-
Vehicle body is subjected to a moment applied at the axle centerlines by applying upward and downward loads at each axle. These loads result in twisting action or torsion moment about the longitudinal x-axis.
1. Cause: When vehicle traverse on an uneven road and front and rear axles experiences a moment.
2. For pure simple torsion torque is applied to one axle and reacted by the other axle.
3. Determination and Result:
Maximum torsion moment is based on the loads at the lighter loaded axle.
Load at front axle 𝑅 and at rear axle 𝑟 can be determined by;
𝒓×𝒕=𝑹×𝒇 (Where 𝑡 and 𝑓 are track width of rear and front axle)
4. Dynamic Factor:
On road: 1.3
Off road: 1.5 to 1.8
Combined bending and torsion-
1. Bending and torsional loads are super imposed. (assumed to be linear)
2. All loads of lighter axle is applied to one bending torsion wheel
3. Determination: Loads can be determined by moment balance.
Lateral Loading-
1. Generated at the tire to ground contact patch
2. Cause: Cornering
3. Result of lateral loading: When inside wheel reaction becomes zero, vehicle rollover.
4. Determination:
i) Practical:
It can either be open loop or close loop
Open loop or directional response: In this case, driver gives some input through steering and corrects it. We study both response and feedback.
Close loop: In this case, driver gives some input and we study vehicle response.
ii) Theoretical:
These loads are balanced by centrifugal force.
Centrifugal acceleration: 𝑉^2/𝑅=𝑔𝑡/2ℎ
Force at CG, at the moment of roll over: 𝑀𝑉2𝑅=𝑀𝑔𝑡2ℎ
Taking ΣF = 0 and ΣM = 0, it can be shown that;
Lateral force at front wheel 𝑌𝑓= (MV^2/R)* [b/(a+b)]
Lateral force at rear wheel 𝑌𝑓= (MV^2/R)* [a/(a+b)]
Width of car and reinforcement provide sufficient bending stiffness to withstand lateral force.
Longitudinal Loading-
1. Cause: When vehicles accelerate and decelerate, longitudinal loads generated
2. Determination:
During acceleration:
Weight transferred from front to back.
Taking ΣM = 0;
Reaction force on the front wheel-
𝑅f={𝑀𝑔(𝐿−𝑎)−𝑀ℎ(𝑑𝑣/𝑑𝑡)}/𝐿
Reaction force on rear wheel-
𝑅r={𝑀𝑔(𝑎)+𝑀ℎ(𝑑𝑣/𝑑𝑡)}/𝐿
During deceleration:
Weight transferred from back to front.
Taking ΣM = 0;
Reaction force on the front wheel-
𝑅f={𝑀𝑔(𝐿−𝑎)+𝑀ℎ(𝑑𝑣/𝑑𝑡)}/𝐿
Reaction force on rear wheel-
𝑅r={𝑀𝑔(𝑎)-𝑀ℎ(𝑑𝑣/𝑑𝑡)}/𝐿
3. Tractive and braking forces add to bending through suspension.
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